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Oracle 1Z0-007 Exam Syllabus Topics:

Oracle Introduction to Oracle9i: SQL Sample Questions:

1. Evaluate the SQL statement:
SELECT LPAD (salary,10,'*')
FROM EMP
WHERE EMP_ID = 1001;
If the employee with the EMP_ID 1001 has a salary of 17000, what is displayed?

A) ****170.00
B) 17000.00
C) **17000.00
D) an error statement
E) 17000*****

2. Which object privileges can be granted on a view?

A) DELETE, INSERT, SELECT, UPDATE
B) none
C) ALTER, DELETE, INSERT, SELECT
D) DELETE, INSERT,SELECT

3. Evaluate this SQL statement:
SELECT e.employee_id, (.15* e.salary) + (.5 * e.commission_pct)
+ (s.sales amount * (.35 * e.bonus)) AS CALC_VALUE FROM employees e, sales s WHERE e.employee_id = s.emp_id;
What will happen if you remove all the parentheses from the calculation?

A) The value displayed in the CALC_VALUE column will be lower.
B) The value displayed in the CALC_VALUE column will be higher.
C) There will be no difference in the value displayed in the CALC_VALUE column.
D) An error will be reported.

4. Evaluate these two SQL statements:
SELECT last_name, salary , hire_date
FROM EMPLOYEES
ORDER BY salary DESC;
SELECT last_name, salary, hire_date
FROM EMPLOYEES
ORDER BY 2 DESC;
What is true about them?

A) The two statements produce identical results.
B) The second statement returns a syntax error.
C) The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.
D) There is no need to specify DESC because the results are sorted in descending order by default.

5. The EMPLOYEES table contains these columns:
EMPLOYEE_ID NUMBER(4)
LAST_NAME VARCHAR2 (25)
JOB_ID VARCHAR2(10)
You want to search for strings that contain 'SA_' in the JOB_ID column. Which SQL statement do you use?

A) SELECT employee_id, last_name, job_id FROM employees WHERE job_id = '%SA_';
B) SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA_';
C) SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA\_%' ESCAPE '\';
D) SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA_' ESCAPE "\";

Solutions: